Sum square difference | Project Euler | Problem #6

URL to the problem page: https://projecteuler.net/problem=6

The sum of the squares of the first ten natural numbers is,
12 + 22 + ... + 102 = 385

The square of the sum of the first ten natural numbers is,
(1 + 2 + ... + 10)2 = 552 = 3025

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 − 385 = 2640.

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

#include <iostream>

using namespace std;

long long power(long long a, long long b) {

    long long result = 1;

    for (int i = 0; i < b; i++) {

        result *= a;

    }

    return result;

}

int main()

{

    long long i, j = 0, number, number2 = 0;

    for (i = 1; i < 101; i++) {

        j += i;

    }

    number = power(j, 2);

    for (i = 1; i < 101; i++) {

        number2 += (power(i, 2));

    }

    cout << "Sum of the squares of the first one hundred natural numbers is  =  " << number << endl;

    cout<<"Square of the sum of the first one hundred natural numbers is  =  " << number2 << endl;

    cout << "Difference between them is  =  " << number - number2 << endl;

    return 0;

}



CLICK TO SEE THE OUTPUT.